Question

Solve the following system using the substitution method.

16x + 3y = 0
8x + y = 1
Solve the following system using the substitution method.

16x + 3y = 0
8x + y = 1
@Mathematics

Answer 1

first solve for y..

basically take one of the equations and make it look like
y= ????

then use that ??? as y in the other equation

Answer 2

i don't know what you mean by that.

Answer 3

solve for y in the second equation..it is : y=-8x+1 and then just take that substitute back into the first equation for 'y' and solve for 'x'

Answer 4

if i give y'all the answers, can you just tell me the right one?

Answer 5

lol but then u dont learn anything =/

Answer 6

SURE I can help with that.

Answer 7

yeaa eyust is right about that as well.

Answer 8

i wouldn't learn anything with you guys telling me how to do it, i suck at math. (:

Answer 9

16x + 3y = 0
8x + y = 1

Take the second equation and isolate the y
y = -8x + 1

The substitute the y in the first equation with -8x + 1
16x + 3(-8x + 1) = 0
16x - 24x + 3 = 0
-8x = -3
/-8 /-8

x = 3/8

The plug in the x for the second equation
8(3/8) + y = 1

24/8 + y = 1
3 + y = 1
-3 -3
y = -2

Then check your work, I hope those are the right answers

Answer 10

its not that hard...as mito showed it to you.

Answer 11

savanna do you have skype?

Answer 12

yeah..?

Answer 13

skype me ill help ya out..

Answer 14

my names the same as on here

Answer 15

mkay, i'll do it in a few.

Answer 16

kk ill prolly be on for the next hour or so