Question

solve x^2+7x-3=0

Answer 1

x^2 + 7x - 3 = 0

a = 1 , b = 7 , c = -3

Sub it into the quadratic formula.

Answer 2

x^2 + (7+ sqrt{61})x/2 + (7-sqrt{61}x)/2 - 3 = 0
x(x+(7+sqrt{61})/2 + (7-sqrt{61})/2)(x+7+sqrt{61})/2) = 0
(x+7+sqrt{61})/2)(x+7-sqrt{61})/2) = 0
x = -7-sqrt{61})/2
x = -7+sqrt{61})/2

Answer 3

Solve using formula for quadratic equation

Answer 4

Or factor by grouping

Answer 5

yes....

Answer 6

see what you have done!

Answer 7

lol
its missing some parenthesis

Answer 8

i can't really read it but i get the idea that it is the
"method of myininaya" lol

Answer 9

lol

Answer 10

:(

Answer 11

no no i like it.

Answer 12

\[x^2 + (7+ \sqrt{61})x/2 + (7-\sqrt{61}x)/2 - 3 \]
\[= 0 x(x+(7+\sqrt{61})/2 + (7-\sqrt{61})/2)(x+7+\sqrt{61})/2)
\]
\[ = 0 (x+7+\sqrt{61})/2)(x+7-\sqrt{61})/2) = 0 x = -7-\sqrt{61})/2 x = -7+\sqrt{61})/2\]

Answer 13

wait i messed that up

Answer 14

\[x^2 + (7+ \sqrt{61})x/2 + (7-\sqrt{61}x)/2 - 3 = 0 \]
\[x(x+(7+\sqrt{61})/2 + (7-\sqrt{61})/2)(x+7+\sqrt{61})/2) = 0\]
\[ (x+7+\sqrt{61})/2)(x+7-\sqrt{61})/2) = 0 \]
\[x = -7-\sqrt{61})/2 x = -7+\sqrt{61})/2\]

Answer 15

got it!

Answer 16

i just copied and pasted hero's answer

Answer 17

come on man, you cant let myin think she has won

Answer 18

oh she is the winner for sure

Answer 19

teachers pet ^

Answer 20

lol