Two banked curves have the same radius. Curve A is banked at an angle of 11.2°, and curve B is banked at an angle of 21.2°. A car can travel around curve A without relying on friction at a speed of 19.0 m/s. At what speed can this car travel around curve B without relying on friction? Two banked curves have the same radius. Curve A is banked at an angle of 11.2°, and curve B is banked at an angle of 21.2°. A car can travel around curve A without relying on friction at a speed of 19.0 m/s. At what speed can this car travel around curve B without relying on friction? @Physics
If a curve is banked, there is a gravitational force pulling down the incline equal to \[mg\sin(\theta)\] Furthermore, if you consider only the component pulling down the incline, the centripetal force required to keep the object moving in a circular path is \[F = \frac{mv^2cos(\theta)}{r} \] therefore, \[mgsin(\theta) = \frac{mv^2cos(\theta)}{r} \] and so \[r = \frac{v^2\cot(\theta)}{g} \] if the two radii are equal, that implies that \[v_1^2\cot(\theta_1) = v_2^2\cot(\theta_2) \] and so \[v_2 = v_1 \sqrt{\frac{\cot(\theta_1)}{\cot(\theta_2)}} \]
if i wanna solve it on my calulator, i will i put cot11.2?
thanks i have solved it using ur solution
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