Question

√-64/(7-6i)-(2-2i)

Answer 1

Would you please use the equation button, I can't understand much like this.

Answer 2

\[\sqrt{64}/(7-6i)-(2-2i)\]

Answer 3

\[\sqrt{-64}/(7-6i)-(2-2i)\]

Answer 4

\[\frac{{\sqrt { - 64} }}{{7 - 6i}} - (2 - 2i)\]

Like this?

Answer 5

the -(2-2i) is also in the denominator. I don't know how to do it

Answer 6

\[\frac{{\sqrt { - 64} }}{{7 - 6i - 2 - 2i}}\] Like this?

Answer 7

yes, except the entire denominator is like this... (7-6i)-(2-2i)

Answer 8

\[\frac{\sqrt{-64}}{(7-6i)-(2-2i)}=\frac{8i}{(7-6i)-(2-2i)}=\frac{8i}{5-4i}\]
This can be expanded if you want.

Answer 9

8i/(5-4i)

Answer 10

that's what I got, but I can't have any "i"s on the denominator. So when simplified, it looked like this...\[-12i/5\]

Answer 11

but that answer is not in the multiple choice. I think it has something to do with complex conjugates

Answer 12

You have to multiply for the complex conjugate.

\[\large \frac{{{\rm{8i(5+ 4i)}}}}{{5 - 4i(5 + 4i)}}\]

Answer 13

that helps

Answer 14

If you split the fractions, you will come up with the expanded form of:
\[-\frac{32}{41}+\frac{40i}{41}\]