Question

4^(3x-2)=1/2^(2x) 4^(3x-2)=1/2^(2x) @Mathematics

Answer 1

write both bases as powers of two
\[4=2^2,\frac{1}{2}=2^{-1}\]

Answer 2

Ooh yesss :P Forgot about that. I got it from there

Answer 3

so you get
\[2^{2(3x-2)}=2^{-1(2x)}\] and then
\[2(3x-2)=-2x\] etc

Answer 4

got it

Answer 5

Thanks :D