suppose that the greatest common divisor of the positive integers X and Y is 21 and the least common multiple of X and Y is 252. The sum of all possible values of X is: a) 20 b) 28 c)420 d)588
the greatest common divisor is the same as the greatest common factor btw.
so we need to look at \[\gcd(x,y)=21 ; lcm(x,y)=\frac{x \cdot y}{\gcd(x,y)}=\frac{x \cdot y}{21} =252 \] \[x \cdot y =252(21)\]
so we can play with these x's and y's right here
so here are two examples of what x can be 252,21 remember we need x>21
126,42
63,84
i think that is it x can be 252,21,126,42,63,84
so the sum of these is 588
all of those pairs i wrote have gcd 21
guess we should also check to see if they have lcm 252
we know the first pair does
the second pair does not 126=126*1 126=42*3 lcm(42,126)=126 so we should throw that pair out
so we have 252,21,63,84 sum is 420 but what is the lcm of 63 and 84...
ok lcm(63,84) is 252 my bad so possible x's are 252,21,63,84 the sum of those is 420
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