Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (across):

Ich werde dir einen Stern geben, wenn du das verstehen kannst und wenn du die folgende Gleichung löst:\[y''-10y'+25y=0.\]Macht's Spaß!

OpenStudy (anonymous):

piensas que vas a espantar me, con esta question?

OpenStudy (across):

Porsupuesto que sí, mi querido amigo. ¿La vas a resolver? :P

OpenStudy (anonymous):

si queria, pero tu horita estoy deprmido, pero tu question es muy facil

OpenStudy (across):

Yo sé que es fácil, pero nadie ha preguntando nada acerca de ecuaciones diferenciales en todo el día...

OpenStudy (anonymous):

eres brilliante, muy buena de la cabeza. Te respeto mucho

OpenStudy (anonymous):

\[y = c_1*e^(5*t) + c_2*e^(-5*t)\] C1 and C2 are constants. That is the general solution of the equation.

OpenStudy (across):

¡Jajaja! Muchísimas gracias por el elogio, lo mismo podría decir de ti. :)

OpenStudy (across):

jprahman is correct! He's today's first winner.

OpenStudy (anonymous):

Awesome! lol

OpenStudy (across):

no waait a moment

OpenStudy (anonymous):

i dont think thats right, the charateristic equation has a double root of 5.

OpenStudy (across):

Almost! You're very close, though. :)

OpenStudy (anonymous):

Oh, yeah. Double root.

OpenStudy (anonymous):

it should be something like:\[y_G=(c_1+c_2t)e^{5t}\]

OpenStudy (anonymous):

should bey = c_1*e^(5*t) = c_2*t*e^(5*t)

OpenStudy (anonymous):

+ not =

OpenStudy (across):

joemath and jprahman win the first round! Well done. :)

OpenStudy (anonymous):

joemath314159 has it right. Go back four postings.

OpenStudy (anonymous):

"I will give thee a star, if you understand this and if you can solve the following equation: [y' -10y' +25y=0.] It's fun!" Google Chrome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!