Question

2e^(2x)+12e^x-54 2e^(2x)+12e^x-54 @Mathematics

Answer 1

sorry, it equals zero D:

Answer 2

2e^(2x)+12e^x-54=0

Answer 3

I'm assuming you mean 2e^(2x)+12e^x-54=0

To make it easier, let e^x = w, so 2w^2+12w-54=0
Also divide the entire equation by 2 to get w^2+6w-27=0

Then just factor normally using whatever method you want (e.g. quadratic formula), and you should get (w+9)(w-3)=0, or w=9 and w=3.

Which means e^x=9 and e^x=3.
Which means x=ln9 and x=ln3.

Answer 4

the only real solution is ln(3)

Answer 5

Very true haha...been a while since I've taken math...