Question

factorise 2k^2+22k+60

I got (2k+12)(k+5)

Answer 1

2k^2+22k+60
2k^2+10k+12k+60
2k(k+5)+12(k+5)
(2k+12)(k+5)

You're correct :)

Answer 2

that is what I thought, but my worksheet gave the answer 2(k+5)(k+6)

Answer 3

2(k+5)(k+6) would give:
2(k^2+11k+30)
= 2k^2 +22k +60

It's just another way of factorising the equation, the answer we both got is still correct, and so is the one your worksheet gives

Answer 4

just factor 2 out of (2k+12)

Answer 5

they are the same 2(k+5)(k+6)=(2k+12)(k+5)
2k+12 = 2(k+6)

Answer 6

take 2 common from 2k+12, that is 2 ( k + 6)

Answer 7

(2k+12)(k+5)
= 2(k+6)(k+5)

Answer 8

so in an exam, which answer would earn the marks?

Answer 9

I guess (2k+12)(k+5) is not factored completely eh?

Answer 10

2(k+6)(k+5) is better

Answer 11

you should always factorize till u can't anymore

Answer 12

I guess so, I would put the second one just to be safe, but in my maths exams the first one will get you the same amount of marks

Answer 13

Great, thanks guys.