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Mathematics 18 Online
OpenStudy (anonymous):

Solve:

OpenStudy (anonymous):

x=

OpenStudy (anonymous):

(log 256 / log 1024 + 4)/3

OpenStudy (anonymous):

this is what i got but im wrong... log1024(260) / 3

OpenStudy (anonymous):

wait hold on 10(3x-4)=8 x=8/5

OpenStudy (anonymous):

\[2^{10(3x-4)}=2^{8}\] 10(3x-4)=8 x=8/5

OpenStudy (anonymous):

thats right but im a little confused

OpenStudy (anonymous):

this is what happens: when you have the exact same bases (it's 2 in the problem) you can focus on just setting the exponents equal to each other

OpenStudy (anonymous):

how would i know that

OpenStudy (anonymous):

i converted \[1024^{3x-4}\] to \[2^{10(3x-4)}\] since 1024=2^10 i did the same with 256 since 2^8=256

OpenStudy (anonymous):

well I'm teaching you

OpenStudy (anonymous):

yeah i know u did but i would never come to that conclusion when i look at this prob

OpenStudy (anonymous):

Sometimes you have to look at a problem from a different angle. I saw that 1024 and 256 were powers of 2 so I converted. It just takes some practice and experimentation.

OpenStudy (anonymous):

can it be solved without doing what u did?

OpenStudy (anonymous):

\[\log{1024^{3x-4}} = \log_{}2 \times 10(3x-4)\] log256 = 8log2 8log2 = 10(3x-4) log2 8=10(3x-4) do the same as I did

OpenStudy (anonymous):

i meant without raising anything to any power

OpenStudy (anonymous):

well the one i just did didn't raise anything to the power. I just took the log of both sides and divided by log2 and solved.

OpenStudy (anonymous):

im still a little confused but ill get this down eventually... thanks for all the help

OpenStudy (anonymous):

no problem. good luck!

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