Solve:
x=
(log 256 / log 1024 + 4)/3
this is what i got but im wrong... log1024(260) / 3
wait hold on 10(3x-4)=8 x=8/5
\[2^{10(3x-4)}=2^{8}\] 10(3x-4)=8 x=8/5
thats right but im a little confused
this is what happens: when you have the exact same bases (it's 2 in the problem) you can focus on just setting the exponents equal to each other
how would i know that
i converted \[1024^{3x-4}\] to \[2^{10(3x-4)}\] since 1024=2^10 i did the same with 256 since 2^8=256
well I'm teaching you
yeah i know u did but i would never come to that conclusion when i look at this prob
Sometimes you have to look at a problem from a different angle. I saw that 1024 and 256 were powers of 2 so I converted. It just takes some practice and experimentation.
can it be solved without doing what u did?
\[\log{1024^{3x-4}} = \log_{}2 \times 10(3x-4)\] log256 = 8log2 8log2 = 10(3x-4) log2 8=10(3x-4) do the same as I did
i meant without raising anything to any power
well the one i just did didn't raise anything to the power. I just took the log of both sides and divided by log2 and solved.
im still a little confused but ill get this down eventually... thanks for all the help
no problem. good luck!
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