Question

square root 3x+7 + square root x+2 = 1

Answer 1

x^2+3x+2=0

Answer 2

Can you show the work please. Thank you ^^;

Answer 3

yah

Answer 4

wait

Answer 5

\[\sqrt{3x+7}=1-\sqrt{x+2}\]
then suaring on both sides and then solv it

Answer 6

hve u got it?

Answer 7

well I squared it and I canceled the squares on the 3x+7 so I am left with square root 3x+7 = (1+square root x+2) squared.

Answer 8

yah then open rite side

Answer 9

it is 1-sq root x+2

Answer 10

sqrt(3x+7)=1-sqrt(x+2)
square both sides: 3x+7 = 1 -2sqrt(x=2)+x+2
2x+4 = -2sqrt(x+2)
Divide by -2
-x-2=sqrt(x+2)
square both sides: x^2+4x+4 = x+2
x^2+3x+2=0
(x+2)(x+1)=0
x=-2, -1 but -1 does not check and is an extraneous root so the answer is -2.

Answer 11

-2 and -1 both

Answer 12

-1 does not check since sqrt(-3+7) +sqrt(-1+2) = 2+1=3 NOT 1

Answer 13

yah ok

Answer 14

Divide by -2 to both sides?

Answer 15

of course

Answer 16

So -2 is just the answer? & Thank you.

Answer 17

yes