Find the six trigonometric functions of each of the following radians. (a) θ=3π/2 (b) θ=5π/4 (c) θ=−π/3 Find the six trigonometric functions of each of the following radians. (a) θ=3π/2 (b) θ=5π/4 (c) θ=−π/3 @Mathematics
yeah
\[\sin(\frac{3\pi}{2})=-1\]
all you have to do is use the unit circle
the six trigonometric functions we are to find is the sine,cosine,tagent,cosec,sec and cotangent
\[\cos(\frac{3\pi}{2})=0\]
\[\tan(\frac{3\pi}{2})=\frac{\sin(\frac{3\pi}{2})}{\cos(\frac{3\pi}{2})}=\frac{-1}{0} DNE\]
\[\cot(\frac{3\pi}{2})=\frac{\cos(\frac{3\pi}{2})}{\sin(\frac{3\pi}{2})}=\frac{0}{-1}=0\]
\[\csc(\frac{3\pi}{2})=\frac{1}{\sin(\frac{3\pi}{2})}=\frac{1}{-1}=-1\]
\[\sec(\frac{3\pi}{2})=\frac{1}{\cos(\frac{3\pi}{2})}=\frac{1}{0} DNE\]
i thought u will 1st find the cordinates that correspondes to each one on a unit circle,and then solve with it?
yep you need to find sine and cosine like i did above
all the other trig functions can either be written in terms of sine or cosine or sine and cosine
sine and cosine are given to you on the unit circle
pls teach me,how is it determined on the unit circle whether is root2/2 or -1 0r 0 is confusing to me
the first coordinate is the cosine of the angle the second coordinate is the sine of the angle
ok the important thing is finding the cosine and sine,tthen i can derive the rest using cosine and sine as their inverse?
inverse?
i mean reciprocal?
you can find csc(theta) by doing the reciprocal of sin(theta) and toy can find sec(theta) by doing reciprocal of cos(theta)
yeah sorry i meant reciprocal,thanks
\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\]
\[\cot(\theta)=\frac{\cos(\theta)}{\sin(\theta)}\]
whats sine and cosine of 5pie/4 in unit circle?
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