Question

If A = 130◦, a = 52, b = 31, solve the triangle. (If there is no solution, give −1 as your
answer.

a) Find B. (If more than one solution, give
the larger one.)
Answer in units of◦
b) Find the corresponding angle C.
Answer in units of◦
c) Find the corresponding side c. If A = 130◦, a = 52, b = 31, solve the triangle. (If there is no solution, give −1 as your
answer.

a) Find B. (If more than one solution, give
the larger one.)
Answer in units of◦
b) Find the corresponding angle C.
Answer in units of◦
c) Find the corresponding side c. @Mathematics

Answer 1

use law of sines to find B
but you might have 2 triangles

Answer 2

\[\frac{\sin(A)}{a}=\frac{\sin(B)}{b}\]

Answer 3

deja vu all over again

Answer 4

\[\frac{\sin(130^o)}{52}=\frac{\sin(B)}{31}\]

Answer 5

\[\frac{31}{52} \sin(130^o)=\sin(B)\]

Answer 6

\[B=\sin^{-1}(\frac{31}{52}\sin(130^o))\]

Answer 7

making

\[B=27.17\]
http://www.wolframalpha.com/input/?i=arcsine%2831*sin%28130%29%2F52%29

Answer 8

only one triangle here, because if A = 130 you don't get two choices for B and C

Answer 9

B'=180-27.17=152.83
but A+B'>180
so you only have one triangle

Answer 10

i found b. its just angle c and side c i didnt find

Answer 11

what myininaya said.

Answer 12

angle C you get because the angles have to add to 180 so it is
\[180-130-27.17\]

Answer 13

A+B=130+27.27=157.17
C=180-(A+B)=22.83

Answer 14

and then repeat process to find side c

Answer 15

i have to do work!!!

Answer 16

me too