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Really need help on this fundamental theorem of calculus problem. @Calculus1
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I thought the answer was sin(5)/5-sin(x^6)/x^6, but that's wrong
derivative of the integral is the "integrand"
\[\frac{-6\sin(x^6)}{x}\]
Try that
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first rewrite this as \[F(x)=-\int_5^{x^6}\frac{\sin(t)}{t}dt\]
then use the chain rule to find the derivative. replace each t by x^6, and then multiply the result by the derivative of x^6 namely 6x^5
Hero you are a lifesaver, thank you.
you get \[\frac{d}{dx}-\int_5^{x^6}\frac{\sin(t)}{t}dt=-\frac{6x^5\sin(x^6)}{x^6}\]
which simplifies to what hero wrote!
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satellite73 thanks for the explanation, extremely helpful.
No Satellite is
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