2pi(integrate)(x(x^2-x^3)dx 2pi(integrate)(x(x^2-x^3)dx @Mathematics

Question

anonymous · Answer

$$2\pi \int\limits_{}^{}x(x^2-x^3)dx$$

anonymous · Answer

$$2\pi * ( {x^4 \over 4} - {x^5 \over 5} + C )$$

anonymous · Answer

need steps? (not that there are many steps, but still) ;)

anonymous · Answer

yes please, but it is supposed to be $$(-\pi*x^4*(4x-5))/10$$

anonymous · Answer

or that is was what i got when i did it on the calculator

anonymous · Answer

forget the 2pi, since it's in front of the integral you can solve the integral and then add 2pi.
You probably put the pi within the integral, the rest of the equation is the same....

anonymous · Answer

$$\int\limits_{}^{}{ x(x^2-x^3)} = \int\limits_{}^{}{x^3-x^4 } = \left[ {1\over 4}x^4 - {1\over5}x^5 + C \right]$$

anonymous · Answer

then multiply by 2pi

anonymous · Answer

ok. thanks :)