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Physics 17 Online
OpenStudy (anonymous):

what is the total charge, in coulombs, of all the electrons in 3.00 mol of hydrogen atoms? what is the total charge, in coulombs, of all the electrons in 3.00 mol of hydrogen atoms? @Physics

OpenStudy (anonymous):

A mole of hydrogen is 6.022 x 10^23 units of hydrogen which will be 6.022 x 10^23 molecules of hydrogen which will be (6.022 x 10^23 times 2, since it's H2) atoms of hydrogen which will be 1.204 x 10^24 atoms of hydrogen. 1 electron per atom. One coulomb is the magnitude (absolute value) of electrical charge in 6.242×10^18 electrons. that makes: 3 * 1.204 x 10^24 / 6.242 x 10^18 = 578660.69 coulomb

OpenStudy (anonymous):

hmmm the answer on the back of my books is 2.89x10^5 coulombs...i'm just wondering how it came to be..

OpenStudy (anonymous):

Number of Hydrogen atoms: \[N=nN_A\]\[N=3\times 6.023\times10^{23}\]\[N=18,069\]Where \[N_A\] the Avogadro constant. Tolal charge: \[Q=N(-e)\]\[Q=18,069\times (-1,6) \times 10^{-19}\]\[Q=-2.89*10^5\] Where \[e\] the elementary charge.

OpenStudy (anonymous):

It's exactly half of my answer, I shouldnt have tried to be smart and simply accept H instead of trying to do the calculation with H2

OpenStudy (anonymous):

It's pretty clear in the question. They're hydrogen atoms not hydrogen molecules.

OpenStudy (anonymous):

Like I said, no need for you to type something like that

OpenStudy (anonymous):

its okay guys, you don't need to argue both! n_n

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