what is the total charge, in coulombs, of all the electrons in 3.00 mol of hydrogen atoms? what is the total charge, in coulombs, of all the electrons in 3.00 mol of hydrogen atoms? @Physics
A mole of hydrogen is 6.022 x 10^23 units of hydrogen which will be 6.022 x 10^23 molecules of hydrogen which will be (6.022 x 10^23 times 2, since it's H2) atoms of hydrogen which will be 1.204 x 10^24 atoms of hydrogen. 1 electron per atom. One coulomb is the magnitude (absolute value) of electrical charge in 6.242×10^18 electrons. that makes: 3 * 1.204 x 10^24 / 6.242 x 10^18 = 578660.69 coulomb
hmmm the answer on the back of my books is 2.89x10^5 coulombs...i'm just wondering how it came to be..
Number of Hydrogen atoms: \[N=nN_A\]\[N=3\times 6.023\times10^{23}\]\[N=18,069\]Where \[N_A\] the Avogadro constant. Tolal charge: \[Q=N(-e)\]\[Q=18,069\times (-1,6) \times 10^{-19}\]\[Q=-2.89*10^5\] Where \[e\] the elementary charge.
It's exactly half of my answer, I shouldnt have tried to be smart and simply accept H instead of trying to do the calculation with H2
It's pretty clear in the question. They're hydrogen atoms not hydrogen molecules.
Like I said, no need for you to type something like that
its okay guys, you don't need to argue both! n_n
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