Question

Find the solution of the equation 4sin^2(theta) - 1 = 0 in the interval [0, pi/2].

Answer 1

\[4\sin^2(x)=1\]
\[\sin^2(x)=\frac{1}{4}\]
\[\sin(x)=\pm\sqrt{\frac{1}{4}}\]
\[\sin(x)=\frac{\sqrt{2}}{2}, \sin(x)=-\frac{\sqrt{2}}{2}\]

Answer 2

so
\[x=\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\]

Answer 3

In my homework, all of the denominators are set at six in the four answer choices. Is something missing?