Question

Hooke's law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 43 cm when the weight is 4 kg, what is the distance when the weight is 5 kg?

Answer 1

F= -kx
(4kg)(-9.8 m/s^2) = -k(.43m)
k = ~91

(5kg)(-9.8 m/s^2) = -91(x)
x = .538m = 53.8cm

Answer 2

so the answer is...?

Answer 3

53.8cm

Answer 4

it says its wrong. It says Type an integer or a simplified fraction.

Answer 5

did you try rounding it to 54 cm?

Answer 6

....no lol

Answer 7

it said thats wrong to

Answer 8

then I have no idea :) I'm pretty sure it's 53.7cm. Maybe someone else will give it a shot and see if they come up with the same thing

Answer 9

err... 53.8

Answer 10

k Thx

Answer 11

I see that it accepted 214/4...which is 53.75. That's why I hate doing math online...the systems are too strict with the form of the answer.