Question

can someone please tell me n=how to find axis of symmetry, vertex for9 (x+3)^2 -5

Answer 1

\[(x+3)^2 - 5\]?

Answer 2

yea

Answer 3

the vertex form of a parabola is y = a(x - h)^2 + k The vertex is (h,k) Make you equation fit that form y = 9(x-(-3))^2 +(-5) So we see that the vertex is (-3,-5)

Answer 4

ignore the 9

Answer 5

the axis of symmetry is x = -3

Answer 6

can someone help me to convert r2 = sen 2 to rectangular

Answer 7

thanks guys

Answer 8

x=rcos
y=rsin
recall

Answer 9

sec=sin