Question

w^4-20w^2-2=0 w^4-20w^2-2=0 @Mathematics

Answer 1

\[w=\pm\sqrt{10+\sqrt{102}}\]
and
\[w=\pm (i\sqrt{\sqrt{102}-10})\]

Answer 2

w squared note x and will get

x2 -20x -2=0
x_1,_2=(20+/- sqrt(400+8))/2 =(20+/- sqrt408)/2 =10+/- sqrt102

than w2=10+/- sqrt102 so
w_1= - sqrt(10+/-sqrt102) and
w_2 = sqrt(10+/-sqrt102)

Answer 3

yes right w_1 sign w_1,_3 and w_2 sign w_2,_4

Answer 4

and hence there are those 4 solutions