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Mathematics 21 Online
OpenStudy (anonymous):

A cable lifts a 1120-kg elevator at a constant velocity for a distance of 39.9 m. What is the work done by the tension in the cable?

OpenStudy (stormfire1):

Since it says constant velocity the upward acceleration due to the tension in the cable must equal the downward acceleration due to gravity. Therefore, T must = -mg So the elevator cable applies a tension of \[T=1120kg*9.8m/s^2=10976N\]W = Fd so the work is \[10976N * 39.9M = 437,942.4J\]

OpenStudy (anonymous):

A person pulls a toboggan for a distance of 37.8 m along the snow with a rope directed 25.7° above the snow. The tension in the rope is 80.4 N. How much work is done on the toboggan by the tension force?

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