9+-3√33 --------- -18
quadratic equations
why can't you just add 3 to 9? why do you have to divide?
is it because 3 is being multiplied by the square root of 33 or is it because 3 has a radical sign by it?
btw this was the process of solving the quadratic equation. the original problem was
-10x^2-9x+1
You can't add the 3 because it's being multiplied by the square root of 33.
so only because it's being multiplied?
Wait is the equation meant to be 9 plus or minus the square root of 33?
yes
9 +- 3 square root of 33
Oh yeah, my bad. When you have two things being multiplied and something added, you have to go by the order of operations. Multiplication comes before adding. So you multiply \[3 * \sqrt{33} = 17.2336\] Then you add 9 and subtract 9. Two different equations \[17.2336 - 9 = 8.2336\] \[17.2336 + 9 = 26.2336\] Divide both by -18. The answers should be -.457 and -1.457
uhmm... without it being put into a decimal
by just leaving the radicals under a square sign
without finding their square root
im guessing it's because it's 3 being multiplied by the square root of 33
Join our real-time social learning platform and learn together with your friends!