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Biology 16 Online
OpenStudy (anonymous):

can anyone help me with protein synthesis mutations?

OpenStudy (blues):

Yes, what's the question?

OpenStudy (anonymous):

so my worksheet says,"using the original strand, add guanine as an extra base immediately after the first start codon in your mRNA sequence"

OpenStudy (anonymous):

the mRNA strand is:AUG,CCA,CUC,CGC,AGA,CGC,UCA,CCU,CUUAGU,GAC,UUA,UGG,UCU,ACG,UAC,AUC,AGU,CCA,UCU,CAC,UCU,CGA,C

OpenStudy (blues):

Is that the question? The insertion of a base is called a frame shift mutation because it shifts by one which 'letters' go into each amino acid 'word' of the protein.

OpenStudy (anonymous):

yea i think so, i think i was just confused, how do you add guanine to that? and then im supposed to transcribe in into a tRNA strand

OpenStudy (blues):

So after the initial AUG, insertion of the guanine will change the next codon to GCC, then the third to ACU, CCG, CAG and so on. I'm not going to type out the entire sequence for you.

OpenStudy (blues):

You're not going to transcribe it into a tRNA strand. tRNA are the little clover leaf shaped molecules made of RNA which float around in the cytoplasm and bring the right amino acid to the ribosome at the right time. If you need to translate the modified mRNA into protein, you're going to need the table, probably found in your textbook, to figure out which codons correspond to which amino acids. Clear?

OpenStudy (anonymous):

is that all it is? even when it says add guanine as an extra base immediately after the first start codon?

OpenStudy (blues):

Yup, that's all. AUG is a start codon; add the base immediately after and then just write out the modified sequence and see which amino acids they correspond to.

OpenStudy (anonymous):

and then i have one more question is that ok?

OpenStudy (blues):

Yes. I'm at my leisure.

OpenStudy (anonymous):

it says to write the original strand, which i did, and underneath i need to transcribe it into a horizontal tRNA anticodon strand, but would i switch out the U's with T's?

OpenStudy (blues):

Exactly. It's that simple.

OpenStudy (anonymous):

ah awesome. your so amazing thank you :)

OpenStudy (blues):

When you're doing this problem, be really carefully about your coding strand vs. your transcript. For example, a C in the coding strand of DNA will be a G in the mRNA. The same goes for the other bases, too.

OpenStudy (anonymous):

thank you thank you thank you thank you

OpenStudy (blues):

Good luck with your homework!

OpenStudy (anonymous):

so it a c will become a g and u will become a t and a g will become a c?

OpenStudy (anonymous):

Its a frameshift mutation and your sequence will become, AUG,GCC,ACU,CCG,CAG,ACG,CUC,ACC,UCU,UAG,UGA,CUU,AUG,GUC,UAC,GUA,CAU,CAG,UCC,AUC,UCA,CUC,UCG,AC see at the 10th and 11th codons, the stop codons came due to this mutation and resulting in a truncated protein.

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