Question

How do I simplify 3/x+1 + 4/x-2?

Answer 1

how do I find the common denomintaro?

Answer 2

take LCM

Answer 3

how?

Answer 4

basically, your equation looks like this:
(3/x) + (1/1) + (4/x) - (2/1) <~ basically what i did was i turned every term into a fraction [recall that 4/1 = is still 4].
so next, you look at all the denominators and see what they have in common, if there's nothing in common, then you just multiply the whole bottom, and that becomes your least common denominator [LCD] or lowest common multiple [LCM].
after that, i don't know how other people do it but what i do is, i take each term and see what they're missing from the LCD / LCM, and i multiply them across. for example.
LCM / LCD = 4x
(3(4)/x) + (1(4x)/1) + (4(4)/x) - (2(4x)/1) / (4x)

Answer 5

(x+1)(x-2) it is the LCM
3/x+1 + 4/x-2 =[ 3(x-2) +4(x+1)]/(x+1)(x-2)

Answer 6

eek, it's

3 4
--- + ---
x+1 x-2

Answer 7

after that, it's just simplifying, (12) + (4x) + (16) - (8x) / 4x

(12 + 16 + 4x -8x) / (4x)

that simplifies to:
(28 - 4x) / 4x

you can simplify that to by factoring out a 4:
4(7 - x) / 4x

the 4's cancel out, there for leaving you with the answer:
(7 - x) / x

Answer 8

can you draw it out? I'm so sorry D:

Answer 9

heh i can but i have to run, the place is closing in 8 minutes. i can continue again in 15~20 mins.

Answer 10

ohh, okay! Please and thank you so much!!