Question

Determine without graphing, whether the given quadratic function has a maximum value or minimum value then find that value.

f(x)=x^2+8

Answer 1

minimum...

Answer 2

f'(x)=2x=0
x=0
f(0)=8
min value is 8

Answer 3

I used calculus, which may be a no-no though :/

Answer 4

lol

Answer 5

Here's another way to think about it without calc
x^2 is always positive, so the larger a negative number you put in, the larger a positive you get out.
therefor the least value it can take is x=0

Answer 6

Quadratics are in the form \[ax^2 + bx + c\]
If a > 0 then you have an absolute minimum

if a < 0 then you have an absolute maximum