Question

Solve the equation.

1/3 log2(x + 6) = log8(3x)

Answer 1

\[{1\over3} \log_2(x + 6) = \log_8(3x)\]right?

Answer 2

yes

Answer 3

\[{1\over3}\log_2(x+6)={\log_23x \over \log_28}={\log_23x \over3}\]can you take it from here?

Answer 4

yes, thanks

Answer 5

change of base is good. also note that if you exponentiate with base 8 you get
\[8^{\log_8(3x)}=8^{\frac{1}{3}\log_2(x+6)}\]
\[3x=2^{\log_2(x+6)}\]
\[3x=x+6\]

Answer 6

So you do :)

Answer 7

Ah sat's a mod now too?
they must have made a round...

Answer 8

i think it just comes with the medals or something. never volunteered.