Question

Double integral surface area:f(x,y)=(2/3)x^{3/2}+cos(x) 0 14 years ago

Answer 1

When the z function creates a boundary, does it define the region?

Answer 2

Is this not a straight double integral then, it's a surface area?

Answer 3

The region is given as a box however the f(x,y) splits the region in half

Answer 4

surface area double integration

Answer 5

sorry I'm too tired for this one now... next time
g'night :)

Answer 6

is it that some part of volume is xy plane and some below it???

Answer 7

or would it just be\[\int\limits_{0}^{1}\int\limits_{0}^{1}\frac{2}{3}x^{3/2}+\cos(x)\]

Answer 8

yes, do it, you'll get a signed volume.

Answer 9

that's for volume but for surface area

Answer 10

\[\int\limits_{0}^{1}\int\limits_{0}^{1}\sqrt{1+f_ x^2+f_ y^2}\]

Answer 11

because for surface area you need a disk or region but it's giving the region already however i'd like to know what this looks like

Answer 12

the question asks to use a computer tosolve it so the integrand is going to be horrible

Answer 13

1.02185199655

Answer 14

zarkon what would the surfacelook like?

Answer 15

not pretty

Answer 16

I'm glad I opted out.

Answer 17

http://alturl.com/f5yz8

Answer 18

true.. there's a way only for getting surface area for surface of revolutions. However what do you use for surface area of such equations.

Answer 19

i was assuming it looked something like a plane

Answer 20

No outkasts formula is more general than those for surface revolutions

Answer 21

and you seem to be partly right :/

Answer 22

partly right?

Answer 23

I mean it looks almost a flat plane, a little curvier though.