Question

Set up the Surface area Double integration
f(x,y)=cos(x^2+y^2) R={(x,y), x^2+y^2<=pi/2}

Answer 1

\[\int\limits_{0}^{2\pi}\int\limits_{0}^{\pi/2}rcos(r^2)drd \theta\]

Answer 2

correct?

Answer 3

yes

Answer 4

actually it'd be pi/4 right? the diameter is pi/4

Answer 5

pi/2