Question

Simplify x^2 - 9 / 2x^2 - 3x -9

Answer 1

Sorry I'm trying to write this out in proper equation

Answer 2

\[\frac{ x^2 - 9}{2x^2 - 3x -9}\]

Answer 3

Like that right?

Answer 4

Yes that's it

Answer 5

Couldn't dot he divide thing

Answer 6

\[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\]
\[\frac{\cancel{(x-3)}(x+3)}{\cancel{(x-3)} (2 x+3)}\]

Answer 7

\[\frac{x+3}{2x+3}\]

Answer 8

Could you explain like step by step, sorry I'm not very good at this

Answer 9

What u have to do is, u have to factor the both numerator and denominator..

Answer 10

After factoring, u will get,
\[\frac{(x-3)(x+3)}{(x-3) (2 x+3)}\]
Now u have to cancel the like terms, leaving u with,
\[\frac{x+3}{2x+3}\]

Answer 11

Thankyou I get it now, as soon as you factorised it's easy from there thanks a lot!

Answer 12

No problem! ^_^