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You obtain 10 ml of a 21% peroxide solution from a mixture of a 15% solution and a 30% solution. How much of the 15% solution is used in the mixture?
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solve \[.15x+.30(10-x)=2.1\]
put x = ml of 15% solution, it will contribute \[.15x\] since the total is 10 the amount of 30% solution will be \[10-x\] and it will contribute \[.30(10-x)\] for a total of \[.15x+.30(10-x)\] you want the total to be 21% of 10 =2.1 so set them equal and solve \[.15x+.30(10-x)=2.1\]
Thank you! I got almost that far but was trying to use .30(y) instead of .30(10-x).
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