Question

find all real values of x such that f(x)=0 f(x)=x^2-3x-28

Answer 1

(x^2-7x)+(4x-28)=0
x(x-7)+4(x-7)=0
(x+4) (x-7)=0
x=-4 or x=7

Answer 2

how did you get the 7

Answer 3

i got to possible numbers that when i add it gives me -3 in the original equation and when i mutiply it it gives me -28
and the two possible factors are -7 and 4

Answer 4

oh you factored it??? okay makes sense now thank you

Answer 5

u welcome :)

Answer 6

wow i get it so much more now hey can you help me with another problem

Answer 7

oh am all yours

Answer 8

its just the equation that changes its f(x)= 2x+6/7 (its a fraction)

Answer 9

would the domain for the first one be (-infinity,-7)(4,infinity)

Answer 10

2x+6/7
(14x+6/7)=0
14x+6=7
14x=7-6
14x=1
x=1/14

Answer 11

u can say all real numbers where x doesa not equal 4
and the 2nd all real numbers where x does not equal 7

Answer 12

so you would use the brackets?

Answer 13

on what?

Answer 14

on the domain

Answer 15

yeah

Answer 16

thanks a lot for your time and stuff

Answer 17

u welcome :)