Question

Any shortcut for finding Pythagorean triples?

Answer 1

\[a=m^2-n^2\]
\[b=2mn\]
\[c=m^2+n^2\]
you can put any natural m and n, and also m>n and generate pythagorean triples

Answer 2

yeah, thanks but what if the number C is big and we hv to find m and n?

Answer 3

you have only c and need to find m and n?

Answer 4

Question is
complete no. series
5,10,13,65,72,?,805
a)790 b)792 c)892 d)690

Answer 5

but it's not pythagorean triple?

Answer 6

above list is c's in pyt. triplets

Answer 7

ah

Answer 8

I can't think of solution, sorry

Answer 9

Anyway Thanks Tom! :)

Answer 10

do you need only answer?

Answer 11

yeah, that would be also be nice but trying to figure out more generous approach for practice purpose :)

Answer 12

I computed and it's triple when c = 792 and c = 892 but answer proabably is 792 because 892>805

Answer 13

good answer tomas

Answer 14

where does the ten come from?

Answer 15

yeah c can't be 10 if it's pythagorean triplet so I don't know, it's not my question :D

Answer 16

oh ok. i got confused because of the question