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Mathematics 25 Online
OpenStudy (anonymous):

The graph of y = x2 is shown below. Using complete sentences, explain how the graph of y = –2(x + 3)2 + 1 would differ from this parabola?

OpenStudy (anonymous):

sorry..not a good artist..the vertex is (0,0)

OpenStudy (anonymous):

|dw:1322072661463:dw|

OpenStudy (karatechopper):

r u doing absolute valuee functions/equations?

OpenStudy (anonymous):

yes..I need hlep with this

OpenStudy (karatechopper):

dont worry i just learned this a couple of days ago i was frustrated too but i can help in this now:)

OpenStudy (anonymous):

thank you

OpenStudy (karatechopper):

r the parentheses supposed to be the absolute value signs? and is x2 x times 2?

OpenStudy (anonymous):

the graph of y=-2(x+3)^2+1 will have curvature downwards and its vertex is at \[(1/\sqrt{2}-3.0)\]

OpenStudy (karatechopper):

woah...^

OpenStudy (anonymous):

yes, and x2 is x^2

OpenStudy (anonymous):

thank you guyz

OpenStudy (karatechopper):

ok

OpenStudy (karatechopper):

well i luckey has given answer so good job

OpenStudy (anonymous):

U still tried

OpenStudy (karatechopper):

yea im proud of my self:) ROBIN AWAY!

OpenStudy (karatechopper):

thnx

myininaya (myininaya):

\[y=-2(x+3)^2+1 \text{ has vertex } (-3,1)\]

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