Question

That's all it says which is why I am throwed off by it.

Answer 1

it must be saying to solve for something..

Answer 2

lol how is that possible? read the question again

Answer 3

This is what I think it is. The average of two numbers, a and b, is given by: A = a + b/2

Answer 4

\[A = \frac{a+b}{2}\]

Answer 5

yea correct

Answer 6

it is the average.. so what now?

Answer 7

hmm?

Answer 8

A = a + b/2 is what I got but it looks incomplete for some reason. That is why I am asking.

Answer 9

lol it needs to give you the numbers.. any two variables from a,b and A or else it is wrong

Answer 10

what if the average of two numbers is 73 and what if one of the nmbers is 59, then what is the other number?

Answer 11

73*2-59
146-59
87

Answer 12

Okay, when I used those numbers, that is what I got. I'm new to this subject so I thought I was wrong. Thanks so much.

Answer 13

you are welcome :D

Answer 14

Did I solve this problem correctly as well? - 2/15 x ≥ 3/16

-(2)/(15)*x>=(3)/(16)
-(2x)/(15)>=(3)/(16)
-(2x)/(15)*15>=(3)/(16)*15
-(2x)/(<X>15<x>)*<X>15<x>>=(3)/(16)*15
-2x*1>=(3)/(16)*15
-2x>=(3)/(16)*15
-2x>=(45)/(16)
-(2x)/(-2)<=(45)/(16)*-(1)/(2)
-(-(2x)/(2))<=(45)/(16)*-(1)/(2)
-(-(<X>2<x>x)/(<X>2<x>))<=(45)/(16)*-(1)/(2)
-(-x)<=(45)/(16)*-(1)/(2)
-1*-x<=(45)/(16)*-(1)/(2)
x<=(45)/(16)*-(1)/(2)
x<=-(45)/(2*16)
x<=-(45)/(32)