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Find the length of the curve ; r(t)=<2t^3/2 , cos(2t) , sin(2t)>, 0<= t <= 3
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I recall a formula for this, something to do with arclengths
Im really sorry , i cant remember the formula.....Anyone can help me....??
Does anyone can give me the solution please.....
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Definitely not; seems wolframalpha didn't parse your input correctly.
\[L=\int\limits_0^3\sqrt{x'(t)^2+y'(t)^2+z'(t)^2}dt\]
I still have no clue.....sry....
\[x=2t^{3/2},x'=3t^{1/2}\]\[y=\cos{2t},y'=-2\sin{2t}\]\[z=\sin{2t},z'=2\cos{2t}\]
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