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Mathematics 16 Online
OpenStudy (anonymous):

Find the length of the curve ; r(t)=<2t^3/2 , cos(2t) , sin(2t)>, 0<= t <= 3

OpenStudy (anonymous):

I recall a formula for this, something to do with arclengths

OpenStudy (anonymous):

Im really sorry , i cant remember the formula.....Anyone can help me....??

OpenStudy (anonymous):

Does anyone can give me the solution please.....

OpenStudy (anonymous):

try http://wolframalpha.com

OpenStudy (anonymous):

Definitely not; seems wolframalpha didn't parse your input correctly.

OpenStudy (nikvist):

\[L=\int\limits_0^3\sqrt{x'(t)^2+y'(t)^2+z'(t)^2}dt\]

OpenStudy (anonymous):

I still have no clue.....sry....

OpenStudy (nikvist):

\[x=2t^{3/2},x'=3t^{1/2}\]\[y=\cos{2t},y'=-2\sin{2t}\]\[z=\sin{2t},z'=2\cos{2t}\]

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