Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

for a function f(x). A) if f(7)=22 then f^-1(22)= B) f^-1(f(c))= **PLEASE HELP**

OpenStudy (anonymous):

can u help me??

OpenStudy (slaaibak):

A) 7 B) c

OpenStudy (anonymous):

how do u do it?

OpenStudy (zarkon):

you should probably specify in the beginning of your problem the f has an inverse.

OpenStudy (anonymous):

the worksheet that i have only said that problem

OpenStudy (anonymous):

thats why i am so lost on this worksheet

OpenStudy (anonymous):

\[f(x)=y\] \[f^{-1}(y)=x\]

OpenStudy (anonymous):

is that how you start it?

OpenStudy (anonymous):

you should use this rule

OpenStudy (anonymous):

ok thank you

myininaya (myininaya):

if this is the problem then A and B may have the answers don't exist since we don't know if f is 1 to 1

myininaya (myininaya):

you should say not enough information

myininaya (myininaya):

as the answer

OpenStudy (slaaibak):

even if the function isn't one-to-one, won't those be at least one of the answers?

OpenStudy (zarkon):

it would be an element of the preimage.

myininaya (myininaya):

f^{-1}(something) should give a unique output for each input something we may have f(-7)=22 also (or f(24)=22 or whatever) so f^{-1}(22)=-7 there could be multiple answers for this and there should not be multiplie answers for this

myininaya (myininaya):

we need f to be 1 to 1

OpenStudy (zarkon):

if \[f:D\to R\] then for any \[x\in R\] \[f^{-1}(x)=\{a\in D|f(a)=x\}\]

myininaya (myininaya):

so you are saying f inverse does not have to be 1 to 1 ?

OpenStudy (zarkon):

if you want a true inverse function...then yes. but you can still look at the preimage no matter what

myininaya (myininaya):

but i don't wanna lol

myininaya (myininaya):

so therefore the answer to me is not enough information

OpenStudy (zarkon):

ok :) I'm sure for these problems we are supposed to assume that the function has an inverse

myininaya (myininaya):

maybe

myininaya (myininaya):

this might be a trick question though

OpenStudy (zarkon):

could be

OpenStudy (slaaibak):

Yeah, it's only to test basic inverse knowledge, my opinion

myininaya (myininaya):

maybe the student should right assuming f is 1 to 1 then the answers are what slaaibak gave without that assumption there is not enough information or assuming f is not 1 to 1 there is not an inverse

myininaya (myininaya):

well it is inverse knowledge to know when an inverse exist

myininaya (myininaya):

god my english sucks like zarkon's write not right

OpenStudy (slaaibak):

haha, yeah, that's correct.

myininaya (myininaya):

good game

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!