Determine the area of the region between the given curves: f(x) = x^3 + 3, x = -2 and y = 11 .....show work please

Question

anonymous · Answer

do you know what is integral?

anonymous · Answer

That is all the info given.

anonymous · Answer

http://www.wolframalpha.com/input/?i=y+%3D+x%5E3+%2B+3%3Bx+%3D+-2%3By+%3D+11

anonymous · Answer

well if he don't know what's integral...

anonymous · Answer

lets assume its f(x)

myininaya · Answer

$$\int\limits_{L }^{U} (t op function-bottom function) dx$$

myininaya · Answer

top function is y=11
bottom function is x^3+3

anonymous · Answer

$$\text{area}=\int_{-1}^a \left[11-f(x)\right]dx$$where a is the x value of the point of intersection between f(x) and your horizontal line.

myininaya · Answer

L is the left intersection which is x=-2  
U is the right intersection which is x=2 since f(2)=11

myininaya · Answer

$$\int\limits_{-2}^{2}(11-[x^3+3]) dx$$
you should be able to do this part
it always helps to draw a visual or see a visual for these types of problems

anonymous · Answer

integrate first than plug in upper/lower bounds?

anonymous · Answer

got 32 as a final answer.

anonymous · Answer

thanks for the help everybody.

anonymous · Answer

yeah frank but draw it first for it to make sense otherwise when you get into 3d volumes or surface area, it makes more sense

anonymous · Answer

it wont make as much sense*