Question

Can you simplify this further?
*Using the quadratic formula to factor x^2-6x-4*
The answer is supposed to be 6(+-)√53 / 2 ,but can't you simplify by 2? 6 and 2 go into 2.
Then could it be 3(+-)√68/1
or no?

Answer 1

Hi neverforgettovisitme

Answer 2

hi

Answer 3

lol

Answer 4

6(+-)√53 / 2 is simplified

Answer 5

:D

Answer 6

answer is is \[3\pm\sqrt{13}\]

Answer 7

wait how is it simplified? in another problem there was a problem where you divided by 3 because it was a common factor

Answer 8

wait i'll go look for it

Answer 9

-9x^2-9x+6

Answer 10

no you cannot because the number inside the radical contains no perfect squares. this is the best you can do

Answer 11

later in the problem the guy got
9(+-)3√33
---------
-18
then he simplified by 3

Answer 12

khanacademy

Answer 13

for
\[-9x^2-9x+6=0\] you can start with
\[3x^2+3x-2=0\] and reduce before you start

Answer 14

oh i see

Answer 15

hold the phone
solution to
\[ x^2-6x-4=0\]is not what you wrote. it is what tomas A wrote

Answer 16

\[\frac{9\pm3\sqrt{33}}{-18}=\]
you can simplify this since
\[\frac{3(3\pm\sqrt{33})}{-6\cdot3}=\]
\[\frac{1(3\pm\sqrt{33})}{-6\cdot1}=\]

Answer 17

\[x^2-6x-4=0\]
\[x^2-6x=4\]
\[(x-3)^2=4+9=13\]
\[x-3=\pm\sqrt{13}\]
\[x=3\pm\sqrt{13}\]