Question

y=x^2+1 find the vertex

Answer 1

\[\Huge \frac{-b}{2a}\]

Answer 2

y=x^2+1 really looks like y=1(x-0)^2+1 and it is in the form y = a(x-h)^2+k where (h,k) is the vertex


We can see that h = 0 and k = 1


So the vertex is (0, 1)

Answer 3

y = x^2 + 1 is just
y = x^2 but shifted vertically by +1.

So the vertex of y = x^2 is just (0,0) and so the vertex of y = x^2 + 1 is (0,1). :)