Question

how to reduce (4.8+j1.6) / (160-j80) by hand the answer is 20+j20 but I can't seem to work it out

Answer 1

It's definitely not that.

(4.8+j1.6) / (160-j80)
= (48+16j)/10 . 1/80 . 1/(2-j)
= 1/800 . (48 + 16j) . (2+j)/(2^2 - i^2)
= 1/4000 . (48 + 16j)(2+j)
= 1/4000 . (96-16 + (48+32).j)
= 1/4000 . (80 + 80j)
= 0.02 + 0.02i

Answer 2

Yeah you are right they converted it to mili without showing that step. Thanks

Answer 3

last line should be j of course; old habits die hard.

Answer 4

haha no worries it all make sense thanks!