Evaluate the integral by interpreting it in terms of areas.
\[\int\limits_{0}^{3} (1/2x-1)dx \]
Is the integrand A. 1/(2x) - 1 B. 1/(2x -1) C. (1/2)x - 1 or something else?
C
Sorry I'm new to the typing an equation thing
Good. So it's f(x) = x/2 - 1. Draw a picture of this and look at what the area is: two triangles. The question is asking you to evaluate the integral by finding the area of those triangles and then combine them appropriately.
remember that area under the x-axis has a negative sign.
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-(1/2)(-1)(1) + (1/2)(1)(1) ?
nope :/
Area right-angled triangle = bh/2, where b = base, h = height.
Hard to be precise when im drawing lol
i know thats where my (1/2) 1 * 1 came from, it's my drawings really
For the triangle on the right b= 2, h = 1, hence area = (1/2).2.1 = 1. But being under the x-axis, the area = -1. Now find the area of the other triangle.
okay so (1/2) * (1/2) * 1 = 1/4 so -1+(1/4) = 3/4
negative *
correct, -3/4
my drawings need to improve! thanks!
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