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OpenStudy (eyust707):
whats question 8?
OpenStudy (anonymous):
hero (hero):
You do realize that the t^3 - t = theta, right?
OpenStudy (anonymous):
ya
hero (hero):
So you can actually set t^3 - t = 90 and solve for t.
you already know that sin(90) = 1, so that means that if you find t, you'll find the t where x = 1
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hero (hero):
This is a little tricky though. Solving for t won't be as simple as that
OpenStudy (anonymous):
no they plugged in values to one that was similar to this
OpenStudy (anonymous):
like 1,0 and 100 but that was when t was an exponent
OpenStudy (anonymous):
shld I skip this one
hero (hero):
For instance, when t is approximately 4.5, x = 1, theta = 90
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hero (hero):
No, you shouldn't.
OpenStudy (anonymous):
well i want to
hero (hero):
I solved that one using a calculator because that's the only way I would know how to solve these
hero (hero):
but, lets do one that you would know how to do
hero (hero):
t^3 - t = theta
when theta = 0
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hero (hero):
Do that one
OpenStudy (anonymous):
I have to hand in this question it is evn
hero (hero):
rld, why are you doing even numbered questions. You're wasting both our time
OpenStudy (anonymous):
no that is what i need to hand in
OpenStudy (anonymous):
t=1
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OpenStudy (anonymous):
or 0
hero (hero):
it's corresponding to angles instead of time. I know it's a natural progression to think that t always responds to time, but it doesn't
OpenStudy (anonymous):
oh right
hero (hero):
You have to finish it though
t can equal 1 or zero
either way theta = 0
so sin(0) = 0
cos(0) = 1
so x = 0, y = 1
OpenStudy (anonymous):
ya but what does t=
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hero (hero):
t = -1, 0, or 1, remember? You calculated it
OpenStudy (anonymous):
i went on to the next one already
hero (hero):
You have to find t, x, and y
hero (hero):
not just t
OpenStudy (anonymous):
I wanna go to bed already
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hero (hero):
lol
OpenStudy (eyust707):
lol
hero (hero):
Nobody is stopping you from going to bed
OpenStudy (anonymous):
idk
OpenStudy (anonymous):
idk
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OpenStudy (eyust707):
for these i just plug in t=0 and it gives me an x and it gives me a y
then i do
t=1
t=2
t=3...
OpenStudy (anonymous):
oh ok
hero (hero):
Yeah, I kind of went backwards with it
OpenStudy (anonymous):
culate it in degrees or radians?
OpenStudy (anonymous):
culate it in degrees or radians?
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OpenStudy (eyust707):
well actually for these we can pick any t we want
hero (hero):
degrees
OpenStudy (eyust707):
so its easier to pick t's that are easy to solve
OpenStudy (anonymous):
oh man that is where i was going wrong
hero (hero):
I hate radians
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OpenStudy (anonymous):
u hate e/t
OpenStudy (eyust707):
i would use t=-1 t=0 and t=1 as a start
OpenStudy (anonymous):
ok
hero (hero):
it doesn't say whether to use radians or degrees
hero (hero):
any input on that eyust
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OpenStudy (eyust707):
well it doesnt really matter.
OpenStudy (eyust707):
so it wants a parameterization
OpenStudy (anonymous):
my book likes to use radians but i dont care i will use what i want to
hero (hero):
yeah, I don't think it matters
OpenStudy (eyust707):
and it tell you its a circle
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OpenStudy (anonymous):
yaa
OpenStudy (eyust707):
so a circle is x^2 + y^2 = r^2
OpenStudy (eyust707):
we know x and we know y
OpenStudy (eyust707):
find r by pulgging in your t values
hero (hero):
actually, we still have to figure out x and y. We're inputting t
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OpenStudy (anonymous):
huh we didn't do it like that
OpenStudy (eyust707):
(cost^3-t)^2 + (sint^3-t) ^2 = r^2
hero (hero):
Oh, lookie there
hero (hero):
You still have to find x and y
OpenStudy (eyust707):
r = 1
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hero (hero):
making it look pretty doesn't change the fact that you still have to calculate the cosine and sine based on t that gives you x and y that you need to solve it
OpenStudy (eyust707):
a parameterization just says change the function of x and y to just t's
hero (hero):
Okay, that's good. My way is just the long way to the same goal. Your approach is superior, no doubt.
OpenStudy (eyust707):
and also tell us when t starts and stops
OpenStudy (anonymous):
ya be nice to eyust
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hero (hero):
You assume that I was being mean to him. rld, you don't need to tell me what to do. I can handle myself
hero (hero):
I have a feeling I will get to bed before rld does
OpenStudy (anonymous):
R u ready to kill me @hero
hero (hero):
Now why would I want to do that?
OpenStudy (anonymous):
cuz i am annoying
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OpenStudy (eyust707):
ok so @ t= 0
we get (1,0)
but the graph for this is nuts!
OpenStudy (eyust707):
it ends up being a solid circle with radius 1 but here let me see if w.a will graph it
OpenStudy (anonymous):
I also got a crazy graph
OpenStudy (eyust707):
ask you professor/teacher about number 8 i honestly am not sure what they want there
OpenStudy (eyust707):
get some rest imma do the same =P
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