Question

same as before... saifoo? slaaibak? help mee?
The sum of the digits of a two digit number is one third of the number. The units digit is 5 more than the 10s digit. What is the number?

Answer 1

I think its
u+5=t
t+u=10t+u/3
but im not really sure.

Answer 2

HI MY BUDDY SAIFOO!!!!

Answer 3

Hello Cloverpetal... =

Answer 4

10t + u = 3(t + u)
t = u - 5

10(u + 5) + u = 3(u + 5 + u)

10u - 50 + u = 6u + 15
5u = 35
u = 7
t = 2

27.

Answer 5

moneybird thanks but thats not really what I was looking for.

Answer 6

slaaibak, why did you multiply that second part of the equation by 3?

Answer 7

Sorry, there are typos in my equations, i'll fix now

Answer 8

thanks

Answer 9

10t + u = 3(t + u)
t = u - 5

10(u - 5) + u = 3(u - 5 + u)
10u - 50 + u = 6u - 15
5u = 35

u = 7
t = 2

27 is the number.

Answer 10

I multiplied it by three, since the sum of the digits is 3 times smaller than the actual number, so by multiplying it by 3, it's equal to the number

Answer 11

why did you subtract five from u when u is five more than the other one?

Answer 12

if you are 15 and you are 5 years older than me, my age = 15 - 5

Answer 13

while you are at it, can you help me with a few more?

Answer 14

I'll do one more, have to go sleep after this

Answer 15

okay...
THe sum of three digits is nine. The tens digit is 1 more than the hundreds digit. When the digits are reversed, the new number is 99 less than the original number. What is the original number?

Answer 16

x + y + z = 9

y = x + 1

100z + 10y + x + 99 = 100x + 10y + z

99z - 99x = -99
z - x = -1


Now we have:

z - x = -1

x + y + z = 9

y = x + 1

In x y z c form:

x + 0y - z + 1 = 0
x + y + z - 9 = 0
x - y + 0z + 1 = 0

x=3
y=4
z=2

342

For some reason I got negative numbers, but it works when I make them positive. I'm way too tired to look into that now.


x=3
y=4
z=2

Answer 17

Should be:

x + y + z = 9
x - y = -1
x - z = 1

Solving gives x=3, y=4, z=2