PLEASE HELP! An aircraft flew a distance of 3000 km from Berlin to Cairo at an average speed of v km/h. i) Write down an expression for time in hours what it took for the journey. ii)The aircraft returned non-stop from by the same route at an average speed of 2v km/h.write an expression to show this. iii)Write down an expression for the time in hours iv)Given that the time for the journey is 4 hours, form an equation in v and solve it. Guys i need you!
OK so do you know the basic equation, rate * time = distance?
Yes I do
OK, so for part (i), plus in the rate and the distance, then isolate t.
Is it: t=3000/v?
yep, exactly
Now the same for (ii)
so 3000/2v?
yep
Now you have written two expressions for the time out and the time back. So if you know the total time for the round trip is 4 hours, can you express that as an equation?
uhm....4=3000/3v ?
no, you can't combine unlike denominators. It's just 4 = (the sum of your two previous expressions)
4=6000/v? This is where i start gettin a bit confused
it's really simple, just literally put a plus sign between the two expressions you computed in part (i) and part (ii)
Are you saying: 4=3000/v+3000/2v?
right
just to be clear, it's \[4 = {3000 \over v} + {2000 \over 2v} \]
Now to solve you multiply the whole thing through by 2v, which means multiplying each term by 2v.
So 4*2v=2v*3000/v+2v*3000/2v
right, now cancel out the extra v's, what do you get?
you should get an equation with no division in it any more
2v*4=v3000+3000
exactly! now collect the v's on one side
2v-3000v=3000/4
hmm, something is fishy here, let me try and figure out what went wrong
OK
ack, ok, haha
So if you have 4 = (3000/v) + (3000/2v) and you multiply by v, all the v's on the right cancel. you get 4 * 2v = 2v*(3000/v) + 2v*(3000/2v)
All the v's cancel out of the right side.
I keep getting 2v*4=3000v+3000 as when the 2v is * by the 3000/v I would end up with that.
By the way thanks for the help so far
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