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Solve using synthetic division: (x^3+x^2-9x-9) divided by (x+1)
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x+1=0 => x=-1 1x^3+1x^2-9x-9 -1 | 1 1 -9 -9 | -1 0 9 ========== 1 0 -9 | 0 \[\frac{x^3+x^2-9x-9}{x+1}=x^2+0x-9=x^2-9\]
how did you write out such pretty formulas?
oh sorry moses i didn't mean to leave you hanging
do frac{ }{ } in the equation editor below
frac{ something}{ something} will give \[\frac{ something}{ something} \]
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\[\int\limits_{a}^{b}f(x) dx\]
{hi}{bi}
see the equation button below
frac{hi}{bi}
\[\frac{hi}{bi} \]
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ah i see. is that latex?
yay!
yes
that is so sexy!
you don't have to go to equation to type there is another way
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teach me latex!!!!!
|dw:1322708862916:dw|
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