All functions that satisfy continuity and smoothness have a derivative. Do all functions that satisfy those conditions have an anti-derivative? Why or why not?
yes they do. the anti- derivative is the integral
can you give a better explanation cus i need to explain
Your first statement is something of a tautology. If a function is 'smooth' at a point or on an interval or whatever, then we mean it has a derivative on that set.
true
continuity implies that you have both a derivative and an integral at that point. consider an integral to be the area under the smooth curve, if the curve is continuous then there exists area underneath it.
Yeah Agree
of course it might not be in a nice closed form, but the fundamental theorem of calculus say "the derivative of the integral is the integrand" so if you have an integrable function \[f(x)\]then \[\int_a^xf(t)dt\] has derivative \[f(x)\]
But I will say this. The conditions for smoothness; i.e., the ability to differentiate are stricter than those to integrate, i.e., the anti-derivative exists. I.e., there are functions which are not differentiable that are (Riemann) integrable. (@moses: continuity most definitely does not imply differentiability. For example f(x) = |x|. This function is continuous everywhere but not differentiable at x = 0)
well since the function isn't smooth
it could be smooth (like gary coleman) or rough, but if it is continuous it is integrable. so it has an "anti - derivative"
that point is not differentiable at x=0 true, but that is a singularity or some sharp point and is not smooth...
smooth = differentiable. That's what smooth means. Anyway, what sat73 said: continuous functions are always integrable. But as we just saw, continuous functions aren't always differentiable.
Ok thanks guys for your help ;D
so why cant you differentiate at x=0 is the tan line fails the horizontal line test? or what? How does it work JamesJ?
Singularity sounds cool What is Singularity in relation to Black Hole?
derivative is a limit. not differentiable means limit does not exist
For f(x) = |x|, the derivative at zero is defined as the limit as a --> 0 of the difference quotient: (f(a) - f(0))/(a-0) = |a|/a. Now it's clear that limit doesn't exist; from the left it is -1; but from the right it is +1. Therefore f is not differentiable at x = 0.
Jamesj then why is the limit taken as a->constant = 0 a bad thing? why do we consider it impossible?
I don't quite understand what you're asking. But a necessary condition for any limit on the real line to exist is that the left-hand limit equal the right-hand limit. In this case it doesn't and therefore the limit doesn't exist. But setting all of that analysis aside, just look at the graph of f(x) = |x|. It's really no surprise that the function doesn't have a derivative at x = 0, as what could it possibly be. Get arbitrarily close to x = 0 from the negative side and the tangent line has slope -1. But from the positive side it is +1. How can we draw a unique tangent line at 0? We can't.
what implies uniqueness when drawing tangent lines?
Technically, the existence of the limit.
james are u a mathmetitian?
yes
That is what it sounds like!!! You have a great understanding of concepts and can explain them clearly
How'd you do it, James How did you get so good at math?
how do i prove an existence of a limit? maybe i need some help with the theory of limits. eps delta proof?
Well u take a limches a from the right hand side and left hand side and if they equal each other than there is a limit
* as x approaches A
hard work mostly: do a lot of examples, and what Paul Halmos said: "Don't just read [the proof]; fight it! "Ask your own questions, look for your own examples, discover your own proofs. Is the hypothesis necessary? Is the converse true? What happens in the classical special case? What about the degenerate cases? Where does the proof use the hypothesis?"
ok guys. off to watch Top Chef now. Bye.
Cool! Thanks I hope I can get as motivated as you are
thanks bye
Bye
My dad want sme to become one!!!!!
I guess my explanation wasn't good enough
I asked this question b4 I approached u
I posted the exact words u told me
Okay, I guess nobody's explanation was good enough. You clearly have tough standards. James will be shocked that you chose my explanation over his.
I dont think he wld care less
I think he would care, because he's a caring person.
Ya but he wldnt care if i used s/o elses explanation over his?!?1? Y wld he care
If s/o is really good at s/t they know it and dont need others approval
rld, you seem so gullible at times, lol it's cute
oh u were joking???
And funniest part about the whole thing is you asking that question.
I definately cant figure u out!!!
Oh trust me. I would never task anyone with trying to do that. Sometimes, I can't even figure myself out.
That is a problem!!!
I don't disagree
Anyway, I'm not going to hold up anymore of your time. I'm sure you should be getting back to work now :P
ya i shld be. so far behind as usual
Besides, I could be watching Smallville right now.
go do that
that wld be educational
Please...if you took one course at my university, you would die by day 3
i dont think so. i wld stick it out
i just need e/t to be perfect
You're too used to finishing courses in two months. If you came here, the course would be done and you would be asking everybody why there's no school tomorrow
LOL
I wld be like i dont even know what i learnt
Goodnight rld :P
Not going to bed yet!!!
me neither but I'm getting off of here. I can't believe I'm addicted to a nerd site.
ya u r
What do ur freinds think that u sit on here all day?????
Nobody knows what I do here. I live in a private dorm
oh cool. hey u r leaving that place or r u?
I would never tell them. That would be too embarrassing
I'm never leaving this town. This is my home
Sorry to disappoint you
y wld i be dissappointed???????
lol, idk
It was just a figure of speech
Okay gn
yup gn
go watch smallville
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