Question

@satellite...can you help me please pretty please on these complex polynomials?

Answer 1

x^3-6x^2+25x

Answer 2

and x^3+9x^2+22x

Answer 3

what are you supposed to do?

Answer 4

factor them out, like we did, but when I took out the x, i found it difficult to factor the inside

Answer 5

use the quadratic formula?

Answer 6

okay, so if i get something like (6 plus or minus √-64)/2 how would it look simplified?

Answer 7

let me check

Answer 8

\[x^3-6x^2+25x\]
\[x(x^2-6x+25)\]
we can solve
\[x^2-6x+25=0\] to factor easy to complete the square
\[x^2-6x-25=0\]
\[x^2-6x=-25\]
\[(x-3)^2=-25+9=-16\]
\[x-3=\pm4i\]
\[x=3\pm 4i\]

Answer 9

so if you want the zeros they are
\[\{0,3+4i,3-4i\}\] and if you want to factor it would be
\[x(x-(3+4i))(x-(3-4i))\]

Answer 10

now if you got
\[\frac{6\pm\sqrt{-64}}{2}\] that is the same because it is
\[\frac{6\pm8i}{2}=3\pm4i\]

Answer 11

oh yeah ^_^

Answer 12

x^3+9x^2+22x ill try doing this one, and can u check my answer?

Answer 13

sure i will do it and wait

Answer 14

i mean first part is just write as
\[x(x^2+9x+22)\] that is easy. then solve the quadratic

Answer 15

okay after u made it equal to -25 where did the 9 come from?

Answer 16

completing the square i turned
\[x^2-6x\] into
\[x^2-6x+9=(x-3)^2\] by adding 9, so i added it on the right as well

Answer 17

so what would be the final answer? i only have like 7 min left to turn it in
:(