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Can someone explain b16 please? (attached) thanks
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sorry. haven't learnt this yet :(
The value of the definite integral \[\int_{-3}^{1}f(x) =4\]is the same as the sum of the areas of regions A, B, and C.
*mind that the area of region B is signed.
Would it be as simple as 8-4 = 4 or do I have to do something else?
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Yeah it's simple. something like \[Area_A -Area_B + Area_C = 4\]
Hmm but you said region B is signed, meaning its negative?
yeah
5 - 3 + A_c = 4 A_c = 2
so wouldnt it be 4 - (5-3) = 2?
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That's also correct :-P
thx
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