Question

Solve using the quadratic formula:
-r^2-5r+1=0

Answer 1

Just use the quadratic formula

Answer 2

I get to \[r=5\pm \sqrt{21}/-2\]
Am I on the right track?

Answer 3

No

Answer 4

Ugh

Answer 5

You must have made a mistake somewhere

Answer 6

I think you subtracted when you should have added

Answer 7

Oh, I know what you did wrong

Answer 8

re-write it like this first:

r^2+5r - 1 = 0

Answer 9

So, \[r=5\pm \sqrt{(-5)}^{2}-4 * 1 * 1 / -2\]

Answer 10

Hero wish me luck going to a chess tournament

Answer 11

You'll get \[r =5\pm \sqrt{29}\div -2\]

Answer 12

LUCK

Answer 13

\[Ax^2 + Bx + C = 0\]
\[x = \frac{-B \pm \sqrt{B^2-4\cdot A \cdot C}}{2\cdot A} \]
is the quadratic formula...

Answer 14

yeah, so i ended up with 25 - 4 / -2
Should I have added?

Answer 15

\[-r^2 - 5r + 1 = 0\]
A = -1, B = -5, C = 1, so
\[x = \frac{5 \pm \sqrt{25+4}}{-2} = \frac{5 \pm \sqrt{29}}{-2}\]

Answer 16

jermurray how do you make a proper divided by line like so?

Answer 17

This system understands LaTeX. You can find the syntax in any basic LaTeX tutorial. In particular, you start an expression with \[, you end it with

Answer 18

\], and in the middle goes

\frac{3}{4}
if you want to type
\[ \frac{3}{4} \]