Question

Use the quadratic formula to solve the equation:
3 x^2 = -3/2 x + 1

Answer 1

ax^2+bx+c=0
\[x=(-b+\sqrt(b^2-4ac))/2a\]
\[ x=(-b-\sqrt(b^2-4ac))/2a\]
3x^2=-3/2x+1
6x^2=-3x+2
6x^2+3x-2=0
here a =6, b=3 c=-2
so the solution can be obtained by substituting these values in the formulae
so
\[x=(-3+sqrt(9+4*6*2))/12\]
\[x=(-3+sqrt(57))/12\]
and the other solution is
\[x=(-3-sqrt(57))/12\]

Answer 2

What did you do to get the 6x^2?

Answer 3

i multiplied the whole equation by 2